Papers of Calculus | Myteachers

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Question:

Using the table of standard integrals, find $\int \frac{1}{\sqrt{x^{2} + 16}}$ .

Answer:

$\int \frac{1}{\sqrt{x^{2} + 16}}$ = ln(x+( $\sqrt{x^{2} + 16}$ )) +c

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